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(svn r9673) -Cleanup: remove spaces before tabs and replace non-indenting tabs with spaces.

release/0.6
rubidium 2007-04-18 22:41:53 +00:00
parent 80c259f64f
commit 2dc5589290
21 changed files with 49 additions and 49 deletions
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10
src/strings.cpp
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@ -421,7 +421,7 @@ static int DeterminePluralForm(int32 n)
* Used in: * Used in:
* Latvian */ * Latvian */
case 3: case 3:
return n%10 == 1 && n%100 != 11 ? 0 : n != 0 ? 1 : 2; return n % 10 == 1 && n % 100 != 11 ? 0 : n != 0 ? 1 : 2;
/* Three forms, special case for one and two /* Three forms, special case for one and two
* Used in: * Used in:
@ -433,25 +433,25 @@ static int DeterminePluralForm(int32 n)
* Used in: * Used in:
* Lithuanian */ * Lithuanian */
case 5: case 5:
return n%10 == 1 && n%100 != 11 ? 0 : n%10 >= 2 && (n%100<10 || n%100 >= 20) ? 1 : 2; return n % 10 == 1 && n % 100 != 11 ? 0 : n % 10 >= 2 && (n % 100 < 10 || n % 100 >= 20) ? 1 : 2;
/* Three forms, special cases for numbers ending in 1 and 2, 3, 4, except those ending in 1[1-4] /* Three forms, special cases for numbers ending in 1 and 2, 3, 4, except those ending in 1[1-4]
* Used in: * Used in:
* Croatian, Czech, Russian, Slovak, Ukrainian */ * Croatian, Czech, Russian, Slovak, Ukrainian */
case 6: case 6:
return n%10 == 1 && n%100 != 11 ? 0 : n%10 >= 2 && n%10 <= 4 && (n%100<10 || n%100 >= 20) ? 1 : 2; return n % 10 == 1 && n % 100 != 11 ? 0 : n % 10 >= 2 && n % 10 <= 4 && (n % 100 < 10 || n % 100 >= 20) ? 1 : 2;
/* Three forms, special case for one and some numbers ending in 2, 3, or 4 /* Three forms, special case for one and some numbers ending in 2, 3, or 4
* Used in: * Used in:
* Polish */ * Polish */
case 7: case 7:
return n == 1 ? 0 : n%10 >= 2 && n%10 <= 4 && (n%100<10 || n%100 >= 20) ? 1 : 2; return n == 1 ? 0 : n % 10 >= 2 && n % 10 <= 4 && (n % 100 < 10 || n % 100 >= 20) ? 1 : 2;
/* Four forms, special case for one and all numbers ending in 02, 03, or 04 /* Four forms, special case for one and all numbers ending in 02, 03, or 04
* Used in: * Used in:
* Slovenian */ * Slovenian */
case 8: case 8:
return n%100 == 1 ? 0 : n%100 == 2 ? 1 : n%100 == 3 || n%100 == 4 ? 2 : 3; return n % 100 == 1 ? 0 : n % 100 == 2 ? 1 : n % 100 == 3 || n % 100 == 4 ? 2 : 3;
} }
} }